Question

We are interested in analyzing data related to college football. Use S to denote the team...

  1. We are interested in analyzing data related to college football. Use S to denote the team is in the SEC and use W to denote a team has a winning season. The probability that a team is in the SEC in the data set is 5.5%. The probability that a team has a winning season is 52.5%. The probability that a team is in the SEC and has a winning season is 3.55%.

    1. What percentage of teams are in the SEC or had a winning season?

    2. What percentage of people teams are in the SEC and did NOT have a winning season?

    3. Given a team had a winning season, what is the probability that they are in the SEC?

    4. What percentage of players are NOT in the SEC and did NOT have a winning season?

    5. Are S and W mutually exclusive events? Why or why not?

    6. Are S and W independent events? Explain, using probabilities.

    7. If we know a team is in the SEC, what is the probability that they had a winning season?

Homework Answers

Answer #1

from given data:

S S' total
W 0.0355 0.4895 0.525
W' 0.0195 0.4555 0.475
total 0.055 0.945 1

a)

percentage of teams are in the SEC or had a winning season=P(S or W) =P(S)+P(W)-P(S n W) =5.5+52.5-3.55=54.45 %

b)

percentage of people teams are in the SEC and did NOT have a winning season

=P(S)-P(S n W) =5.5-3.55 =1.95 %

c)

P(S |W )=P(S n W)/P(W) =3.55/52.5 =0.0676

d)

percentage of players are NOT in the SEC and did NOT have a winning season

=100-P(S or W) =100-54.45 =45.55 %

e)
S and W are not mutually exclusive since P(S and W) is not equal to 0

f)

since P(S)*P(W) is not equal to P(S n W) ; therefore S and W are not independent events.

g)

P(W |S)=P(S n W)/P(S) =3.55/5.5 =0.6455

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