Question

12. Cards: Suppose you and a friend are playing cards and you are each dealt 4 cards. You have a 10, Jack, Queen, and King in your hand. You are about to dealt one more card. What is the probability that you are dealt an Ace given that

a. Your friend has no Aces in his hand.

b. Your friend has exactly one ace in his hand.

Answer #1

**ANSWER::**

**12Q)**

**a)**

Number of cards remaining in deck = 52 - (2x4) = 44

If your friend has no aces in his hand, number of aces remaining in the deck = 4

P(you are dealt an ace | no aces in your friend's hand) = 4/44

**=
1/11**

**b)**

Number of cards remaining in deck = 52 - (2x4) = 44

If your friend has exactly one ace in his hand, number of aces remaining in the deck = 3

P(you are dealt an ace | exactly one ace in your friend's hand)
= **3/44**

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