Question

31. An obtained chi square of 9.53 was calculated and the critical chi square was 18.48....

31. An obtained chi square of 9.53 was calculated and the critical chi square was 18.48. What should be concluded from these results?

a.

The result is both statistically significant and important.

b.

The variables are independent.

c.

The null hypothesis must be rejected.

d.

The information is incomplete; nothing can be concluded.

Homework Answers

Answer #1

Here, the calculated chi- sq. Value is 9.53 which is less than critical chi-sq. value (=18.48). So, we do not reject the null hypothesis.

So, option B is correct.

As under null hypothesis on test of independence of attributes we have , H0: the variables are independent.

Statistically significant means there is difference Between observed and expected frequency i.e. we reject the null hypothesis. So, option a and c are not true as we are not rejecting the null hypothesis.

Also, option D is not correct as the information is complete.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
For df=1, the critical values for Pearson's chi-square are 3.84 (p=0.05) and 6.63 (p=0.01). If you...
For df=1, the critical values for Pearson's chi-square are 3.84 (p=0.05) and 6.63 (p=0.01). If you calculated chi-square for a set of categorical variables and received a value of 4.52, what would this indicate? a. The result is significant at both p=0.05 and p=0.01 b. The result is significant at p=0.05 but not at p=0.01 c. The result is significant at p=0.01 but not at p=0.05 d.The result is not significant at either p=0.05 or p=0.01 a. The result is...
PLEASE ANSWER ALL QUESTIONS ! 1. When performing a Chi-Square test, what is the critical value...
PLEASE ANSWER ALL QUESTIONS ! 1. When performing a Chi-Square test, what is the critical value between the accept and reject regions for a test with 5 classes and 25 observations at the 5% level of significance? Select one: a. 11.070 b. 2.87 c. 2.60 d. 9.488 2. True or False: A hypothesis is a statement about a population developed for the purpose of testing. Select one: True False 3. If you ACCEPT the null hypothesis while performing a Chi-Square...
Which of the following statements is true in the context of a chi-square goodness-of-fit test? Select...
Which of the following statements is true in the context of a chi-square goodness-of-fit test? Select one: a. The critical value will come from the standard normal table if the sample size exceeds 30. b. The degrees of freedom for determining the critical value will be the number of categories minus 1. c. A very large test statistic will result in the null not being rejected. d. The null hypothesis will be rejected for a small value of the test...
Which of the following statements is true in the context of a chi-square goodness-of-fit test? Select...
Which of the following statements is true in the context of a chi-square goodness-of-fit test? Select one: a. The degrees of freedom for determining the critical value will be the number of categories minus 1. b. A very large test statistic will result in the null not being rejected. c. The null hypothesis will be rejected for a small value of the test statistic. d. The critical value will come from the standard normal table if the sample size exceeds...
The table lists survey results obtained from a random sample of different crime victims. Use a...
The table lists survey results obtained from a random sample of different crime victims. Use a 0.01 significance level to test the claim that the type of crime is independent of whether the criminal was a stranger. LOADING... Click the icon to view the table. a. State the null and the alternative hypotheses. Choose the correct answer below. A. The null​ hypothesis: The type of crime is somehow related to whether the criminal is a stranger. The alternative​ hypothesis: The...
Which of the following is the conclusion that ought to be reached if the calculated value...
Which of the following is the conclusion that ought to be reached if the calculated value of the F statistic in an analysis of variance (ANOVA) fails to exceed the critical value? The null hypothesis should be accepted. There is not enough power to reveal the differences among the group means. The wrong test has been conducted and a different test would have found a statistically significant result. The null hypothesis of no differences among the group means cannot be...
The P-value for a chi-square test is always one-tailed. This is true because of all of...
The P-value for a chi-square test is always one-tailed. This is true because of all of the following reasons, EXCEPT: Group of answer choices Observed data that is either higher or lower than the null hypothesis predicts will result in a positive chi-square value. Only a large positive value of chi-square provides stronger evidence to conclude HA. A chi-square distribution is skewed. The chi-square statistic is always positive, unlike a z or t statistic which can be ether positive or...
(Question 3) A researcher wishes to test the null hypothesis that a die is fair against...
(Question 3) A researcher wishes to test the null hypothesis that a die is fair against the alternative hypotheses that a die is not fair. A die is rolled 360 times. There are 6 categories. The observed value of the chi square statistic is 10.23. 3. (Use the chi square table to answer this question) In her written report of the results of the experiment, the researcher should declare, The result is significant at the 1% level, that is, the...
Chapter 18 Chi-square – Test of Independence Certain editors at Sage like to think they’re a...
Chapter 18 Chi-square – Test of Independence Certain editors at Sage like to think they’re a bit of a whiz at soccer. To see how well they play compared with Sussex lecturers and postgraduates, we invited various employees of Sage to join in our soccer matches. Every player was allowed only to play in one match. Over many matches, we counted the number of players that scored goals. After running a chi-square test of independence, determine whether or not the...
Assignment #7: One-sample Chi-Square Directions: Use the Chi-Square option in the Nonparametric Tests menu to answer...
Assignment #7: One-sample Chi-Square Directions: Use the Chi-Square option in the Nonparametric Tests menu to answer the questions based on the following scenario. (Assume a level of significance of .05 and use information from the scenario to determine the expected frequencies for each category) During the analysis of the district data, it was determined that one high school had substantially higher Graduate Exit Exam scores than the state average and the averages of high schools in the surrounding districts. To...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT