If n=28, ¯xx(x-bar)=46, and s=7, find the margin of error at a
95% confidence level
Give your answer to two decimal places.
solution
Given that,
s =7
n = 28
Degrees of freedom = df = n - 1 =28- 1 = 27
At 95% confidence level the t is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
t /2,df = t0.025,27 = 2.052 ( using student t table)
Margin of error = E = t/2,df * (s /n)
= 2.052 * (7 / 28)
= 2.71
Margin of error = E = 2.71
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