Determine whether or not the table is a valid probability
distribution of a discrete random variable. Explain fully.
a.
x |
-2 |
0 |
2 |
4 |
P(x) |
0.3 |
0.5 |
0.2 |
0.1 |
b.
x |
0.5 |
0.25 |
0.25 |
P(x) |
-0.4 |
0.6 |
0.8 |
c.
x |
1.1 |
2.5 |
4.1 |
4.6 |
5.3 |
P(x) |
0.16 |
0.14 |
0.11 |
0.27 |
0.22 |
In part a) we find that the probabilities sum up to 1 and are non negative. So it represents a valid probability distribution of a discrete random variable.
In part b) we find that the first value of P(x) is negative. Probability is a non negative quantity always and lies between 0& 1. So (b) cannot represent a probability distribution.
In part c) although the probabilities are non negative, they don't sum up to 1. For being a probability distribution of a random variable, the sum of the probabilities should be 1. Here the sum is 0.68. Hence, (c) also fails to be a valid probability distribution.
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