Question

Could you please tell me the parameters of this, and how to put it into R?

And which distribution is being used?

And how to graph them in R?

Number of errors per page of a long manuscript has a Poisson distribution with lambda=0.91 per page. Suppose a page is selected at random. What is the probability that there will be more than two errors on this page?

Answer 1

Let X be number of errors per page of a long manuscript.

X follows Poisson(lambda = 0.91)

The distribution we are using is Poisson distribution and it has a parameter λ = 0.91

The probability that there will be more than two errors on randomly selected page,

P(X > 2)

In R, ppois(x, lambda, lower.tail = FALSE) gives P(X > x)

> ppois(2, 0.91, lower.tail = FALSE)

[1] 0.064514

The probability that there will be more than two errors on randomly selected page would be 0.0645