Question

A club professional at a major golf course claims that the course is so tough that the median score is greater than 75. The scores from a random sample of 20 professional golfers are listed below. Test the club professionalȇs claim. Use a= 0.05.

74 72 75 75 78 77 69 81 75 80 72 74 76 76 83 81 75 77 78 68  

Answer 1

calculate mean and standard deviation for the given data

This is right tailed test, for α = 0.05 and df = 19
Critical value of t is 1.729.
Hence reject H0 if t > 1.729

Test statistic,
t = (xbar - mu)/(s/sqrt(n))
t = (75.8 - 75)/(3.8471/sqrt(20))
t = 1.1925

since test staistic is less than critical t value we do not reject H0

There is not enough evidence conclude that median score is greater than 75