An engineer wishes to determine the width of a particular
electronic component. If she knows that the standard deviation is
1.9 mm, how many of these components should she consider to be 90%
sure of knowing the mean will be within ±0.5±0.5 mm?
Given that,
standard deviation =s = =1.9
Margin of error = E = 0.5
At 90% confidence level
= 1 - 90%
= 1 - 0.90 =0.10
/2
= 0.05
Z/2
= Z0.05 = 1.65
sample size = n = [Z/2* / E] 2
n = ( 1.65 * 1.9 / 0.5 )2
n =40
Sample size = n =40
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