A new soft drink is being market tested. A sample of 400 individuals participated in the taste test and 140 indicated that they like the taste. If less than 40% of the population likes the taste of the new soft drink, the company will not begin a national marketing campaign for the product. Set up the appropriate hypotheses and test, using the critical value and p-value approaches, at the .05 level of significance (alpha) whether less than 40% of the population likes the soft drink. State your conclusion about the hypotheses. Should the manufacturer begin marketing the product based on your conclusions? Why or why not?
Given
n = 400 Sample Size
140 out of 400 individuals like the taste
p̂ = 140/400 = 0.35
Sample proportion of individuals who like the
taste
p = 0.4 (40%)
Population (Standardised)
proportion
α = 0.05 Level of
significance
The null and alternative hypothesis are
Ho : p = 0.4
H1 : p < 0.4
This is a left tailed test
Test statistic
We find z, the test statistic as
where
z = -2.0412
p-value
We find p-value using Standard Normal tables or Excel function
NORM.S.DIST
p-value = NORM.S.DIST(-2.0412, TRUE)
p-value = 0.0206
Critical Value of Z
We find z-critical using Standard Normal tables or Excel function
NORM.S.INV
α = 0.05
z-critical = NORM.S.INV(0.05)
z-critical = -1.645
Rejection Criteria
Reject Ho if calculated test statistic z < -1.645
or Reject Ho if p-value < 0.05
0.0206 < 0.05
That is p-value < α
Hence, we Reject Ho
Also,
-2.0412 < -1.645
that is calculated test statistic z < z-critical
Hence, we Reject Ho
Conclusion :
Reject Ho. There is sufficient evidence at α = 0.05, to conclude
that less than 40% of the population likes the soft
drink
Since the hypothesis test proves that less than 40% of
the population likes the soft drink
the manufacturer should not begin marketing the
product.
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