you have not stated whether it is z test or t test.
i have find it for both z test and t test as follows,
1) if it is z test
P-Value = 0.6892
2) if it is t test
P-Value = 0.6932
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Explanation:
test is two tailed test
sample size (n) =22
test statistics= -0.4
1)
for Z test
P-Value = 2 * P(z < -0.4)
using normal z table we get
P(z < -0.4) = 0.3446
P-Value = 2 * 0.3446
P-Value = 0.6892
2)
we are using excel command to get p-value for t-test
We get p-value as
P-Value = 0.6932
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