According to a recent survey, the average earnings in a certain city were $41 comma 80041,800 in Educational Services and $77 comma 40077,400 in the Financial Services industry.
a) Suppose the standard deviation of earnings in Educational Services for the whole of the city was $11 comma 20011,200 and we want the standard deviation of average earnings in our survey to be $10001000.
What sample size do we need to take?
b) Suppose we used a sample of size 370370 for our estimate of average earnings in Financial Services and the standard deviation of earnings in our survey was $19 comma 40019,400.
What is the standard error of the average earnings in Financial Services?
According to a recent survey, the average earnings in a certain city were $41,800 in Educational Services and $77,400 in the Financial Services industry.
a) Suppose the standard deviation of earnings in Educational Services for the whole of the city was $11,200 and we want the standard deviation of average earnings in our survey to be $1000.
What sample size do we need to take?
standard deviation of sample average earnings =sd/sqrt(n)
11200/sqrt(n) =1000
Sqrt(n) = 11200/1000 = 11.2
n=125.44
= 125 ( rounded)
b) Suppose we used a sample of size 370 for our estimate of average earnings in Financial Services and the standard deviation of earnings in our survey was $19,400.
What is the standard error of the average earnings in Financial Services?
standard error = sd/sqrt(n) = 19400/sqrt(370)
=1008.56
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