Q-10 (1 of 1)
A soft drink manufacturer wishes to know how many soft drinks adults drink each week. They want to construct a 95% confidence interval for the mean and are assuming that the population standard deviation for the number of soft drinks consumed each week is 1.1. The study found that for a sample of 949 adults the mean number of soft drinks consumed per week is 3.6 Construct the desired confidence interval. Round your answers to one decimal place.
Solution :
Given that,
Sample size = n = 949
Z/2
= 1.96
Margin of error = E = Z/2*
(
/
n)
= 1.96 * (1.1 /
949)
= 0.1
At 95% confidence interval estimate of the population mean is,
- E <
<
+ E
3.6 - 0.1 <
< 3.6 + 0.1
3.5 <
< 3.7
(3.5, 3.7)
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