given that the mean pulse rate is 67.3 beats per minute and a standard deviation of 10.3 bpm calculate at least what percentage of data will contain 87.9 bpm using chebyshev's theorem
We have : = 67.3, = 10.3
We need to find, the percentage of data will contain at least 87.9 bpm
For any data set, at least 1-1/k2 % of data values lies within k standard deviations of the mean. k > 1
First we find value of k .
+ k * = 87.9
67.3 + k * 10.3 = 87.9
10.3 k = 87.9 - 67.3
10.3 k = 20.6
so, k = 2
Hence,
At least 75% of data will contain 87.9 bpm.
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