Question

Suppose the following data are selected randomly from a population of normally distributed values. 46 51...

Suppose the following data are selected randomly from a population of normally distributed values. 46 51 43 48 44 57 54 39 40 48 45 39 45 Construct a 95% confidence interval to estimate the population mean. Appendix A Statistical Tables (Round the intermediate values to 2 decimal places. Round your answers to 2 decimal places.)

≤ μ ≤

Homework Answers

Answer #1

Answer)

First we need to find the mean and s.d of the given data

Mean = 46.08

S.d = 5.53

N = 13

As the population standard deviation is unknown here we will use t distribution to construct the interval

Degrees of freedom is = n-1 = 12

For 12 dof and 95% confidence level, critical value t from t table is = 2.18

Margin of error (MOE) = t*s.d/√n = 2.18*5.53/√13 = 3.3417

Interval is given by

(Mean - MOE, Mean + MOE)

[42.7383, 49.4217].

You can be 95% confident that the population mean (μ) falls between 42.7383 and 49.4217.

42.74 < u < 49.42

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A sample of 20 test scores were taken from a normally distributed population produced the following...
A sample of 20 test scores were taken from a normally distributed population produced the following data. Suppose we want to estimate the true mean test score of all using the ample values. 44 52 31 48 46 39 47 36 41 57 45 52 31 48 46 39 47 38 41 59 Identify the parameter. Is it known? Make a 95% confidence interval for the mean score of all. Take the population standard deviation as 2.5.
Construct 90%, 95%, and 99% confidence intervals to estimate μ from the following data. State the...
Construct 90%, 95%, and 99% confidence intervals to estimate μ from the following data. State the point estimate. Assume the data come from a normally distributed population. 13.7 11.6 11.9 13.0 12.5 11.4 12.0 11.7 11.8 13.7 Appendix A Statistical Tables (Round the intermediate values to 4 decimal places. Round your answers to 2 decimal places.) 90% confidence interval: enter the lower limit of the 90% confidence interval ≤ μ ≤ enter the upper limit of the 90% confidence interval...
2a. Describe the sample and population you are studying. I am studying customers' satisfaction level with...
2a. Describe the sample and population you are studying. I am studying customers' satisfaction level with their car insurance plan. 2b. Calculate the sample mean and sample standard deviation for your variable. Keep at least four decimal places. 2c. Calculate the standard error and the margin of error for a 90% confidence interval. Keep at least four decimal places. Data: 36 18 66 43 28 39 47 40 24 46 48 57 36 58 39 62 43 65 74 36...
Construct 90%, 95%, and 99% confidence intervals to estimate μ from the following data. State the...
Construct 90%, 95%, and 99% confidence intervals to estimate μ from the following data. State the point estimate. Assume the data come from a normally distributed population. 13.1 11.6 11.9 12.0 12.5 11.4 12.0 11.7 11.8 13.1 Appendix A Statistical Tables (Round the intermediate values to 4 decimal places. Round your answers to 2 decimal places.) 90% confidence interval: enter the lower limit of the 90% confidence interval ≤ μ ≤ enter the upper limit of the 90% confidence interval...
A random sample of small-business managers was given a leadership style questionnaire. The results were scaled...
A random sample of small-business managers was given a leadership style questionnaire. The results were scaled so that each manager received a score for initiative. Suppose the following data are a random sample of these scores. 43 42 41 39 38 31 41 43 35 45 30 33 35 44 36 43 39 33 39 41 41 33 35 36 41 33 43 38 41 42 44 35 36 33 38 32 30 43 42 Assuming σ is 3.891, use...
The workweek for adults in the US that work full time is normally distributed with a...
The workweek for adults in the US that work full time is normally distributed with a mean of 47 hours. A newly hired engineer at a start-up company believes that employees at start-up companies work more on average then working adults in the US. She asks 15 engineering friends at start-ups for the lengths in hours of their workweek. Their responses are shown in the table below. Test the claim using a 5% level of significance. See Excel for Data....
The following data were selected randomly from a normally distributed population of values represent the percent...
The following data were selected randomly from a normally distributed population of values represent the percent of fat in a certain type of steak burger. The manufacturer claims that the mean fat percent is less than 20%. Use 10% level of significance and population variance 9 to test the manufacturer claim. 21, 18, 19, 16, 18, 24, 22, 19, 24, 14, 18, 15.
A random sample of n=12 values taken from a normally distributed population resulted in the sample...
A random sample of n=12 values taken from a normally distributed population resulted in the sample values below. Use the sample information to construct 95 % confidence interval estimate for the population mean. 107 93 90 114 90 98 115 112 110 108 97 96 The 95% confidence interval is from $__________ to $__________ . (Round to two decimal places as needed. Use ascending order.)
A random sample of n=12 values taken from a normally distributed population resulted in the sample...
A random sample of n=12 values taken from a normally distributed population resulted in the sample values below. Use the sample information to construct a 95% confidence interval estimate for the population mean. The 95% confidence interval is from $______to $_______ 96 101 93 96 109 95 111 110 108 103 104 110 *round using two decimal places as needed using ascending order* PLEASE EXPLAIN STEP BY STEP
The percentage of titanium in an alloy used in aerospace castings is measured in 51 randomly...
The percentage of titanium in an alloy used in aerospace castings is measured in 51 randomly selected parts. The sample standard deviation is s = 0.40. Construct a 95% two-sided confidence interval for σ. Assume population is approximately normally distributed. Round your answers to 4 decimal places.