In a survey, 15 people were asked how much they spent on their
child's last birthday gift. The results were roughly bell-shaped
with a mean of $48 and standard deviation of $7. Construct a
confidence interval at a 90% confidence level.
Give your answers to one decimal place.
___±_____
Solution :
degrees of freedom = n - 1 = 15 - 1 = 14
t/2,df = t0.05,14 = 1.761
Margin of error = E = t/2,df * (s /n)
= 1.761 * (7 / 15)
Margin of error = E = 3.2
The 90% confidence interval estimate of the population mean is,
± E
= 48 ± 3.2
= ( 44.8, 51.2 )
Get Answers For Free
Most questions answered within 1 hours.