A random sample of 100 observations Denote byX1,X2,...,X100, were selected from a population with a mean μ= 40 and variance σ2= 400.
Determine P(38< ̄X <43), where ̄X= (X1+X2+...+X100)/100.
This is a normal distribution question with
Sample size (n) = 100
Since we know that
P(38.0 < x < 43.0)=?
This implies that
P(38.0 < x < 43.0) = P(-1.0 < z < 1.5) = P(Z < 1.5) - P(Z < -1.0)
P(38.0 < x < 43.0) = 0.9331927987311419 - 0.15865525393145707
PS: you have to refer z score table to find the final probabilities.
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