Find the I.Q (Intelligence Quotient ) that is the 67th percentile in a population of I.Q scores that is Normally distributed with mean 110 and standard deviation 12:
Here Z is the standard normal variable
Let c be the I.Q that is the 67th percentile
As c from a population of I.Q scores that is Normally distributed with mean 110 and standard deviation 12
so, will follow standard normal
67th percentile means 67% data lies below the IQ that is 67th percentile
so, probability = 67%/100% = 0.67
Now we get the equation
From z table we get the value of
so, c = 115.28
Answer: The I.Q that is the 67th percentile in a population is 115.28
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