Use the sample data and confidence level given below to complete parts (a) through (d).
A research institute poll asked respondents if they felt vulnerable to identity theft.
In the n=974 and x=551 who said "yes." Use a 90% confidence level?
A.Find the best point estimate of the population proportion P=
B.Identify the value of the margin of error E=
C. Construct the confidence interval. ___< P< __
Solution :
Given that,
Point estimate = sample proportion = = x / n = 551 / 974 = 0.566
Z/2 = 1.645
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.645 * (((0.566 * 0.434) / 974)
= 0.026
A 90% confidence interval for population proportion p is ,
- E < p < + E
0.566 - 0.026 < p < 0.566 + 0.026
0.540 < p < 0.592
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