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The university football team has 11 games on its schedule. Assume that the probability of winning...

The university football team has 11 games on its schedule. Assume that the probability of winning each game is .75 and that there are no ties. Assuming independence, what is the probability that this years team will have a winning season, that is, that the team will win at least six games?

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Given that:

The university football team has 11 games on its schedule. Assume that the probability of winning each game is .75 and that there are no ties.

According to provided details, the number of games on schedule are 11, let the probability of winning be p = 0.75 . It is provided that the games are independent of each other. The problem is to find the probability that the team will win at least 6 games out of 11

Let X denote the event of winning a game So, X b(11, p). thus the probability that the team will win at least 6 games out of 11 is calculated as

; x = 0,1,......11

So, the probability that the team will win at least 6 games is 0.9654

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