Question

3. A box contains eight defective and twelve good transistors. If five transistors are drawn, with replacement, in succession, find the probability of drawing at most three defective transistors using the tables provided.

Pdf for formulas: http://docdro.id/HLm3Ta5

Answer #1

here this is binomial distirbution with probability of defecitve p=8/(8+12)=0.4

and n=20

therefore probability of drawing at most three defective transistors using the tables provided =P(X<=3)

= =0.0160

answered by: anonymous

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