Question

Assume that a procedure yields a binomial distribution with a trial repeated n = 18 times....

Assume that a procedure yields a binomial distribution with a trial repeated n = 18 times. Find the probability of X > 4 successes given the probability p = 0.27 of success on a single trial.

P(X>4)=

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Answer #1

Solution:- Given that p = 0.27, n = 18

P(X > 4) = 1 - P(X <= 4) = 1 - 0.4406 = 0.5594

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