Question

Gasoline prices 1980 1.131 1.207 1.252 1.264 1.266 1.269 1.271 1.267 1.257 1.250 1.250 1.258 mean,...

Gasoline prices
1980 1.131 1.207 1.252 1.264 1.266 1.269 1.271 1.267 1.257 1.250 1.250 1.258
mean,
median,
mode,
midrange
standard deviation

Homework Answers

Answer #1

Solution:- Given that Gasoline prices 1980

1.131 1.207 1.252 1.264 1.266 1.269 1.271 1.267 1.257 1.250 1.250 1.258

mean = sum of terms /number of terms

= (1.131 + 1.207 + 1.252 + 1.264 + 1.266 + 1.269 + 1.271 + 1.267 + 1.257 + 1.250 + 1.250 + 1.258)/12

= 1.245

median = The median is the middle number in a sorted list of numbers. So, to find the median, we need to place the numbers in value order and find the middle number.

= (1.257+1.258)/2

= 1.2575

= 1.258

Mode = The mode of a set of data is the value in the set that occurs most often.

= 1.250

midrange = (1.131 + 1.271)/2 = 1.201

Standard deviation:-

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
2. Given the following data, calculate the mean, median, mode, midrange, standard deviation, and variance. 14.35,...
2. Given the following data, calculate the mean, median, mode, midrange, standard deviation, and variance. 14.35, 17.22, 18.90, 20.02, 34.43, 12.85, 18.49, 7.62, 19.93 (a) Mean (b) Median (c) Mode (d) Range (e) Standard Deviation (f) Variance
DETROIT                               ANN ARBOR 2008       59  &n
DETROIT                               ANN ARBOR 2008       59                           2008       61 2009       60                           2009       58 2010       61                           2010       60 2011       69                           2011       68 2012       66                           2012       67 2013       62                           2013       64 2014       64                           2014       66 2015       71                           2015       70 2016       69                           2016       72 2017       66                           2017       64 What is the mean, median, mode, range, midrange, variance, and standard deviation for both cities? Detroit Mean Median Mode Range Midrange Variance Standard Deviation Ann Arbor Mean Median Mode Range Midrange Variance Standard Deviation Make sure...
Find every possible statistic of your data. (Mean, median, mode, standard deviation, variance, midrange, range, etc.)...
Find every possible statistic of your data. (Mean, median, mode, standard deviation, variance, midrange, range, etc.) explain what these statistics mean in the context of your data without defining or using a formula. Is the statistic realistic of the population? Is it skewed? How is it distributed? What level of measurement is it? 2005 Kelly Blue Book Used Cars Price Mean $21,343.14 Standard Error $348.61 Median $18,025.00 Mode $10,921.95 Standard Deviation $9,884.85 Sample Variance 97710314.9 Range $62,116.54 Minimum $8,638.93 Maximum...
The number of hot dogs all of the contestants ate are listed below. Find the mean,...
The number of hot dogs all of the contestants ate are listed below. Find the mean, median, mode, and midrange. 31 55 78 80 44 61 80 91 54 74 80 94 1. Is the data provided above a sample or a population? Please explain. 2. What formula will you use for the mean? Please explain how you determined the correct formula for the mean? Find the mean, median, mode and midrange for the data.
Which of the following measures of central tendency or variability must (if it exists) be an...
Which of the following measures of central tendency or variability must (if it exists) be an actual data point. a) midrange b)mean c) mode d) variance e) standard f) deviation g) median
descriptive statistics for the closing stock prices of two companies for several trading periods are shown...
descriptive statistics for the closing stock prices of two companies for several trading periods are shown below. baba inc, mean ,4.04 standard error, 0.11 median, 4.07 mode, 3.59 mean ,4.04 standard error, 0.11 median, 4.07 mode, 3.59 standard deviation 1.13 sample variance 1.28 kurtosis -1.10 skewness 0.04 range 3.98 minimum 2.00 maximum 5.98 sum 416.05 count 103 maman inc. mean 16.41 standard error 0.22 median 16.83 mode 16.59 standard deviation 2.34 sample variance 5.48 kurtosis 9.10 skewness -2.85 range 12.57...
For the following Simple data ( separately ) : 18 , 30 , 14 , 21...
For the following Simple data ( separately ) : 18 , 30 , 14 , 21 , 25 , 24 , 34 , 15 , 25 , 26 , 18 , 24 , 18 , 33 , 20 1) Find ( Mean , Mode , Median , Range , Midrange , Standard Deviation , Variance )
At one point the average price of regular unleaded gasoline was ​$3.593.59 per gallon. Assume that...
At one point the average price of regular unleaded gasoline was ​$3.593.59 per gallon. Assume that the standard deviation price per gallon is ​$0.080.08 per gallon and use​ Chebyshev's inequality to answer the following.​(a) What percentage of gasoline stations had prices within 33 standard deviations of the​ mean?​(b) What percentage of gasoline stations had prices within 2.52.5 standard deviations of the​ mean? What are the gasoline prices that are within 2.52.5 standard deviations of the​ mean?​(c) What is the minimum...
At one point the average price of regular unleaded gasoline was ​$3.72 per gallon. Assume that...
At one point the average price of regular unleaded gasoline was ​$3.72 per gallon. Assume that the standard deviation price per gallon is ​$0.06 per gallon and use​ Chebyshev's inequality to answer the following. (a) What percentage of gasoline stations had prices within 2 standard deviations of the​ mean? ​(b) What percentage of gasoline stations had prices within 2.5 standard deviations of the​ mean? What are the gasoline prices that are within 2.5 standard deviations of the​ mean? ​(c) What...
At one point the average price of regular unleaded gasoline was ?$3.57 per gallon. Assume that...
At one point the average price of regular unleaded gasoline was ?$3.57 per gallon. Assume that the standard deviation price per gallon is ?$0.07 per gallon and use? Chebyshev's inequality to answer the following. ?(a) What percentage of gasoline stations had prices within 4 standard deviations of the? mean? ? (b) What percentage of gasoline stations had prices within 2.5 standard deviations of the? mean? What are the gasoline prices that are within 2.5 standard deviations of the? mean? ?...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT