The standard error here is computed as:
The test statistic here is computed as:
For n1 + n2 - 2 = 198 degrees of freedom, we have from the t distribution tables here:
p = 2P(t198 > 1.5) = 2*0.0677 = 0.1354
As the p-value here is 0.1354 > 0.1 which is the level of significance, therefore the test is not significant here and we cannot reject the null hypothesis here. Therefore we have insufficient evidence here that there is a difference in two means here.
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