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Find the margin of error for the given confidence level and values of x and n....

Find the margin of error for the given confidence level and values of x and n. x=79, n=187, 98% confidence level

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Answer #1

Solution :

Given that,

Point estimate = sample proportion = = x / n = 79 / 187 = 0.422

1 - = 1 - 0.422 = 0.578

Z/2 = 2.326

Margin of error = E = Z / 2 * (( * (1 - )) / n)

= 2.326 * (((0.422 * 0.578) / 187)

Margin of error = E = 0.084

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