Professor Cramer determines a final grade based on attendance, two papers, three major tests, and a final exam. Each of these activities has a total of 100 possible points. However, the activities carry different weights. Attendance is worth 6%, each paper is worth 10%, each test is worth 16%, and the final is worth 26%.
(a) What is the average for a student with 77 on attendance, 86
on the first paper, 68 on the second paper, 63 on test 1, 75 on
test 2, 89 on test 3, and 61 on the final exam? (Round your answer
to one decimal place.)
(b) Compute the average for a student with the above scores on the
papers, tests, and final exam, but with a score of only 24 on
attendance. (Round your answer to one decimal place.)
Answer:
a)
Given,
The weighted average = wx / w
substitute values
= [77*0.06 + 86*0.10 + 68*0.10 + 63*0.16 + 75*0.16 + 89*0.16 + 61*0.26] / [0.06 + 0.10 + 0.16 + 0.16 + 0.16 + 0.26]
= 72.2 / 0.9
= 80.2
b)
The weighted average = wx / w
substitute values
= [24*0.06 + 86*0.10 + 68*0.10 + 63*0.16 + 75*0.16 + 89*0.16 + 61*0.26] / [0.06 + 0.10 + 0.16 + 0.16 + 0.16 + 0.26]
= 69.02 / 0.9
= 76.7
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