Question

A random sample of 40 adults with no children under the age of 18 years results...

A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.96 ​hours, with a standard deviation of 2.35 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.32 ​hours, with a standard deviation of 1.52 hours. Construct and interpret a 95​% confidence interval for the mean difference in leisure time between adults with no children and adults with children (μ1−μ2)

Let μ1 represent the mean leisure hours of adults with no children under the age of 18 μ2 represent the mean leisure hours of adults with children under the age of 18.

The 95​%confidence interval for (μ1−μ2 is) the range from ____hours to____hours.

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A random sample of 40 adults with no children under the age of 18 years results...
A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.04 hours, with a standard deviation of 2.26 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.28 ​hours, with a standard deviation of 1.73 hours. Construct and interpret a 90​% confidence interval for the mean difference in leisure time between adults with no...
A random sample of 40 adults with no children under the age of 18 years results...
A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.62 ​hours, with a standard deviation of 2.45 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.41 ​hours, with a standard deviation of 1.64 hours. Construct and interpret a 90​% confidence interval for the mean difference in leisure time between adults with no...
A random sample of 4040 adults with no children under the age of 18 years results...
A random sample of 4040 adults with no children under the age of 18 years results in a mean daily leisure time of 5.345.34 ​hours, with a standard deviation of 2.372.37 hours. A random sample of 4040 adults with children under the age of 18 results in a mean daily leisure time of 4.124.12 ​hours, with a standard deviation of 1.641.64 hours. Construct and interpret a 9090​% confidence interval for the mean difference in leisure time between adults with no...
In December 2001, 38% of adults with children under the age of 18 reported that their...
In December 2001, 38% of adults with children under the age of 18 reported that their family at dinner together seven nights a week. In recent poll, 403 of 1122 adults with children under the age of 18 reported that their family at dinner together seven nights a week. the researcher wishes to estimate the current proportion of families with children under the age of 18 who eat dinner together seven nights a week with 95% confidence. a. what type...
In a previous​ poll, 34​% of adults with children under the age of 18 reported that...
In a previous​ poll, 34​% of adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Suppose​ that, in a more recent​ poll, 372 of 1146 adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Is there sufficient evidence that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has​ decreased?...
A medical researcher claims that 5% of children under 18 years of age have asthma. In...
A medical researcher claims that 5% of children under 18 years of age have asthma. In a random sample of 300 children under 18 years of age, 24 children had asthma. Is this evidence that more than 5% of children under 18 years of age have asthma? The null and alternative Hypotheses for the Test are: HO : p = 0.05 HA : p > 0.05 The P-value for this test is 0.0086. What does the P-value mean in the...
In a previous​ poll, 35​% of adults with children under the age of 18 reported that...
In a previous​ poll, 35​% of adults with children under the age of 18 reported that their family ate dinner together 7 nights a week. Suppose​ that, in a more recent​ poll, 445 of 1300 adults with children under the age of 18 reported that their family ate dinner together 7 nights a week. Is there sufficient evidence that the proportion of families with children under the age of 18 who eat dinner together 7 nights a week has decreased...
In a previous​ poll, 41​% of adults with children under the age of 18 reported that...
In a previous​ poll, 41​% of adults with children under the age of 18 reported that their family ate dinner together 7 nights a week. Suppose​ that, in a more recent​ poll, 401 of 1050 adults with children under the age of 18 reported that their family ate dinner together 7 nights a week. Is there sufficient evidence that the proportion of families with children under the age of 18 who eat dinner together 7 nights a week has decreased...
2. A nutritionist claims that children under the age of 10 years are consuming more than...
2. A nutritionist claims that children under the age of 10 years are consuming more than the U.S. Food and Drug Administration's recommended daily allowance of sodium, which is 2400 mg. A random sample of 22 children under the age of 10 was taken to measure their daily consumption of sodium. The sample mean was 2993 mg., with a sample standard deviation of s=1489 mg. Be sure to check if the conditions are met, and show how you checked them  ...
Question 1 In December 2001, 38% of adults with children under the age of 18 reported...
Question 1 In December 2001, 38% of adults with children under the age of 18 reported that their family ate dinner together seven nights a week. A sociologist wishes to estimate the percentage of families that eat dinner together seven nights a week. She wants to her estimate to be within 3% at the 95% confidence level. (Show your work for the following questions.) a. What size of sample should she take if she uses the 2001 percentage as a...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT