Question

E and F be any experiments with their probabilities as p(E) = 0.73 and P(F) = 0.58

1. the two given experiments are mutually exclusive, find p(E or F)

2. If the two given experiments are not mutually exclusive and p(E&F)= 0.45 , find p(E U F).

Please provide with all steps TIA

Answer 1

(1) If the two experiments E and F are mutually exclusive, then they cannot occur at the same time. This means, that p(E and F) = 0. Hence, p(E or F) = p(E) + p(F) - p(E and F) = 0.73 + 0.58 - 0 = 1.31. (This value is impossible, because probability values lie between 0 and 1! The probability value of either E and F is wrong. The addition of the two probabilities should give a probability value which is less than 1.)

(2) If the two experiments E and F are not mutually exclusive, then they can occur at the same time. This means, that p(E and F) is not equal to 0. Hence, p(E U F) = p(E or F) = p(E) + p(F) - p(E and F) = 0.73 + 0.58 - 0.45 = 0.86.

answered by: anonymous