Question

Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.)

? = 29; ? = 3.6

P(x ? 30) =

Answer 1

Solution :

Given that ,

mean = = 29

standard deviation = = 3.6

P(X 30) = 1 - P(x 30)

= 1 - P((x - ) / (30 - 29) / 3.6)

= 1 - P(z < 0.2778)   Using standard normal table,

= 1 - 0.6094

= 0.3906

P(X 30) = 0.3906