Question

The following table contains observed frequencies for a sample of 200.
Test for independence of the row and column variables using a=05 . Compute the value of the test statistic (to 2 decimals). The P-value is - Select your answer -less than .005between .005 and .01between .01 and .025between .025 and .05between .05 and .10greater than .10 What is your conclusion? - Select your answer -Cannot reject the assumption that rows and columns are independentConclude the row variable and column variable are not independent |

Answer #1

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The following table contains observed frequencies for a sample
of .
Column Variable
Row Variable
A
B
C
P
30
58
60
Q
20
12
20
Test for independence of the row and column variables
using .
Compute the value of the test statistic (to 2
decimals).
The -value is - Select your answer -less than .005between .005
and .01between .01 and .025between .025 and .05between .05 and
.10greater than .10Item 2
What is your conclusion?
- Select your answer -Cannot reject...

The following table contains observed frequencies for a sample
of 200.
Column Variable
Row Variable A B C
P 30 56 65
Q 20 14 15
If you cant read it AP=30 AQ=20 BP=56 BQ=14 CP=65 CQ=15
Test for independence of the row and column variables using a
=.05. Compute the value of the x^2 test statistic (to 2 decimals).
The p-value=?

The following table contains observed frequencies for a sample
of 260.
Column
Variable
Row Variable
A
B
C
P
15
30
15
Q
25
55
10
R
40
25
45
Test for independence of the row and column variables using
a=0.05 .
Compute the x^2 value of the test statistic (to 3
decimals). ________
The p-value is _________
_________(Cannot Conclude / Conclude) that the column
variable is not independent of the row variable.

The following table contains observed frequencies for a sample
of 200.
Row
Variable
Column Variable
A
B
C
P
24
48
54
Q
26
22
26
Test for independence of the row and column variables using
α = 0.05.
State the null and alternative hypotheses.
H0: The column variable is independent of
the row variable.
Ha: The column variable is not independent of
the row variable.H0: Variable P is not
independent of variable Q.
Ha: Variable P is independent of...

Use the sample data
below to test the hypotheses
:
: Not all population
proportions are the same
Populations
Response
1
2
3
Yes
200
200
91
No
150
200
109
where is the
population proportion of yes responses for population . Using a
level of significance 0.05.
The p-value is -
Select your answer -less than .005between .005 and .01between .01
and .025between .025 and .05between .05 and .10greater than .10
What is your
conclusion?
- Select your answer...

The following table contains observed frequencies for a sample
of 240.
Row
Variable
Column Variable
A
B
C
P
15
25
15
Q
30
60
25
R
15
20
35
Test for independence of the row and column variables using
α = 0.05.
State the null and alternative hypotheses.
H0: Variable P is not independent of
variables Q and R.
Ha: Variable P is independent of variables Q
and R.H0: Variable P is independent of
variables Q and R.
Ha:...

1.) The following table contains observed frequencies for a
sample of 200.
Row
Variable
Column Variable
A
B
C
P
24
48
54
Q
26
22
26
Test for independence of the row and column variables using
α = 0.05.
Find the value of the test statistic. (Round your answer
to three decimal places.) = ???
Find the p-value. (Round your answer to four
decimal places.) = ????
2.) A magazine subscriber study asked, "In the past 12 months,
when...

The calculations for a factorial experiment involving four
levels of factor A, three levels of factor B, and three
replications resulted in the following data: ,STT = 261, SSA=21,
SSB=22, SSAB=165
Set up the ANOVA table and test for significance using a=.05 .
Show entries to 2 decimals, if necessary. If the answer is zero
enter “0”.
Source of Variation
Sum of Squares
Degrees of Freedom
Mean Square
F
p-value
Factor A
Factor B
Interaction
Error
Total
The -value for...

In an experiment designed to test the output levels of three
different treatments, the following results were obtained: SST= 420
SSTR=150 NT=19. Set up the ANOVA table and test for any significant
difference between the mean output levels of the three treatments.
Use A=.05.
Source
of Variation
Sum
of Squares
Degrees
of Freedom
Mean Square
(to 2 decimals)
(to 2 decimals)
-value
(to 4 decimals)
Treatments
150
Error
Total
420
The P-value is - Select your answer -less than .01between...

xi
2
6
9
13
20
yi
7
18
9
26
23
The estimated regression equation is ŷ = 7.6 +
.9x.
What is the value of the standard error of the estimate (to 4
decimals)?
What is the value of the t test statistic (to 2
decimals)?
What is the p-value?
- Select your answer -less than .01between .01 and .02between .02
and .05between .05 and .10between .10 and .20between .20 and
.40greater than .40Item 3
What is your...

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