Use this information to answer the following questions: We have data here from a sample of middle aged people. The columns represent the level of sports they played while the rows represent whether they have developed arthritis later in life.
Observed |
College |
High school |
Did not play |
||
Arthritis |
10 |
9 |
24 |
||
No arthritis |
61 |
206 |
548 |
||
Run the appropriate test to see if playing sports has an effect on arthritis late in life.
What are your hypotheses?
Ho: Data fits the hypothesized distribution; Ho: Data does not fit the hypothesized distribution
Ho: No association between the variables; Ha: There is an association between the variable
Ho: All groups are the same; Ha: All groups are different
Run the appropriate test to see if playing sports has an effect on arthritis late in life.
What is your resulting test statistic?
What is the appropriate degrees of freedom?
What is your best estimate of the p-val?
What decision should you make?
Ans:
Hypothesis statements:
Ho: No association between the variables;
Ha: There is an association between the variable
Chi square test for independence:
Observed(fo) | ||||
college | high school | did not play | Total | |
Arthritis | 10 | 9 | 24 | 43 |
No arthritis | 61 | 206 | 548 | 815 |
Total | 71 | 215 | 572 | 858 |
Expected(fe) | ||||
college | high school | did not play | Total | |
Arthritis | 3.56 | 10.78 | 28.67 | 43 |
No arthritis | 67.44 | 204.22 | 543.33 | 815 |
Total | 71 | 215 | 572 | 858 |
Chi square=(fo-fe)^2/fe | ||||
college | high school | did not play | Total | |
Arthritis | 11.662 | 0.292 | 0.760 | 12.714 |
No arthritis | 0.615 | 0.015 | 0.040 | 0.671 |
Total | 12.277 | 0.308 | 0.800 | 13.385 |
Test statistic:
Chi square=13.385
df=(2-1)*(3-1)=2
p-value=CHIDIST(13.385,2)=0.0012
Reject the null hypothesis.
Get Answers For Free
Most questions answered within 1 hours.