The life of a fully-charged cell phone battery is normally distributed with a mean of 14 hours with a standard deviation of 3 hours. What is the probability that 25 batteries last less than 16 hours?
Solution :
Given that ,
mean = = 14
standard deviation = σ = 3
n = 25
= 14
= / n = 3 / 25=0.6
P( <16 ) = P[( - ) / < (16-14) / 0.6]
= P(z <3.33 )
Using z table
= 0.9996
probability= 0.9996
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