Question

56% of students need some form of remedial math, before they take college level math courses. If 4 students are picked at random:

a) Create a probability distribution for the number of students who need remedial math (R) (Label columns and rows; use only what you need; show work-some or all)

b) What is the probability of having at least 1 who needs remedial math

Answer 1

(a)

Binomial Distribution

n = 4

p = 0.56

q = 1 - p = 0.44

Probability Distribution of X = Number of students who need remedial math is given below:

Number of students who need remedial math (x)	Probability
0
1
2
3
4

Thus,

Probability Distribution of X = Number of students who need remedial math is given below:

Number of students who need remedial math (x)	Probability
0
1
2
3
4

(b)

P(X1) = 0.1908 + 0.3643 + 0.3091 + 0.0983 = 0.9625

So,

Answer is:

0.9625