A lumber company is making boards that are 2716.0 millimeters tall. If the boards are too long they must be trimmed, and if they are too short they cannot be used. A sample of 23 boards is made, and it is found that they have a mean of 2714.9 millimeters with a standard deviation of 12.0. Is there evidence at the 0.1 level that the boards are either too long or too short? Assume the population distribution is approximately normal.
Step 1 of 5:
State the null and alternative hypotheses.
Step 2 of 5:
Find the value of the test statistic. Round your answer to three decimal places.
boards are either too long or too short? Assume the population distribution is approximately normal.
Step 3 of 5:
Specify if the test is one-tailed or two-tailed.
Step 4 of 5:
Determine the decision rule for rejecting the null hypothesis. Round your answer to three decimal places.
Step 5 of 5:
Make the decision to reject or fail to reject the null hypothesis
Step 1 of 5:
H0: Null Hypothesis : = 2716
HA: Alternative Hypothesis: 2716
Step 2 of 5:
n = sample size = 23
= sample mean = 2714.9
s = sample SD = 12
SE = s/
= 12/ = 2.5022
Test statistic is:
t = ( - )/SE
= (2714.9 - 2716)/2.5022 = - 0.4396
Step 3 of 5:
Two tail test
Step 4 of 5:
ndf = 23 - 1 = 22
= 0.10
From Table, critical value of t = - 1.321
Decision rule for rejecting the null hypothesis:
t < - 1.321
Step 5 of 5:
Since calculated value of t = - 0.4396 is greater than critical value of t = - 1.321, Fail to reject H0.
Conclusion:
There is no evidence at the 0.1 level that the boards are too long or too short.
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