Question

A data set includes 103 body temperatures of healthy adult humans having a mean of 98.9 degrees F and a standard deviation of 0.67 degrees F. Construct a 99% confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6 degrees F as the mean body temperature?

Answer #1

*Given,*

*X_bar = 98.9*

*s = 0.67*

*n = 103*

*Now calculate 99% confidence interval is*

*CI = x_bar
z*(s/n)*

*z value for 99% confidence interval is 2.58.*

*CI = 98.9
2.58 *(0.67103)*

*= 98.9
0.170*

*CI = 98.9 - 0.170 and CI = 98.9 + 0.170*

*CI = 98.73 and CI = 99.07*

*Therefore 99% confidence interval is (98.73,99.07).*

A data set includes 103 body temperatures of healthy adult
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A data set includes 103 body temperatures of healthy adult
humans having a mean of 98.9degreesF and a standard deviation of
0.67degreesF. Construct a 99% confidence interval estimate of the
mean body temperature of all healthy humans. What does the sample
suggest about the use of 98.6degreesF as the mean body
temperature
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