Question

A data set includes 103 body temperatures of healthy adult humans having a mean of 98.9 degrees F and a standard deviation of 0.67 degrees F. Construct a 99​% confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6 degrees F as the mean body​ temperature?

Answer 1

Given,

X_bar = 98.9

s = 0.67

n = 103

Now calculate 99% confidence interval is

CI = x_bar z*(s/n)

z value for 99% confidence interval is 2.58.

CI = 98.9 2.58 *(0.67103)

= 98.9 0.170

CI = 98.9 - 0.170 and CI = 98.9 + 0.170

CI = 98.73 and CI = 99.07

Therefore 99% confidence interval is (98.73,99.07).