Question

# In a recent Super Bowl, a TV network predicted that 37% of the audience would express...

In a recent Super Bowl, a TV network predicted that 37% of the audience would express an interest in seeing one of the forthcoming television shows. The network ran commercials for these shows during the Super Bowl. The day after the Super Bowl and Advertising Group sampled 118 people who saw the commercials and found that 41 of them said they would watch one of the television shows.

Suppose you are have the following null and alternative hypotheses for a test you are running:

Ho : p = 0.37

Ha : p < 0.37

Calculate the test statistic, rounded to 3 decimal places

z=

= x / n = 41/118=0.3475

P0 = 0.37

1 - P0 = 1 -0.37=0.63

n=118

Test statistic = z

= - P0 / [P0 * (1 - P0 ) / n]

=0.3475-0.37 / [(0.37*0.63) /118]

Z= -0.5062

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