Question

If n=32, ¯ x (x-bar)=44, and s=7, find the margin of error at a 95% confidence level (use at least two decimal places)

Answer 1

Solution :

Given that,

s =7

n = 32

Degrees of freedom = df = n - 1 = 32- 1 =31

At 95% confidence level the t is ,

= 1 - 95% = 1 - 0.95 = 0.05

  / 2= 0.05 / 2 = 0.025

t /2,df = t0.025,31 = 2.040 ( using student t table)

Margin of error = E = t/2,df * (s /n)

=2.040 * (7 / 32)

= 2.5244

Margin of error = E =2.5244

answered by: anonymous