Test H0 : p = 0.25 vs Ha : p < 0.25 using the sample results p^=0.16 with n = 100
Solution :
This is the left tailed test .
The null and alternative hypothesis is
H0 : p = 0.25
Ha : p < 0.25
= 0.16
P0 = 0.25
1 - P0 = 1 - 0.25 = 0.75
Test statistic = z
= - P0 / [P0 * (1 - P0 ) / n]
=0.16 - 0.25 / [0.25 - 0.75 / 100]
= −2.08
Test statistic z value = - 2.08
P-value = 0.0188
= 0.05
P-value <
Reject the null hypothesis .
There is sufficient evidence to suggest that
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