Question

Find the indicated probability using the standard normal distribution.

​P(zless than<negative 1.71−1.71orzgreater than>1.711.71​)

​P(zless than<negative 1.71−1.71or zgreater than>1.711.71​)equals=nothing

​(Round to four decimal places as​ needed.)

Answer 1

Z is a standard normal variate

That means , the distribution of z is normal (symmetrical bell shaped) with mean = 0 and variance =1

We have to find , P( z < -1.71 or z > 1.71)

P( z < -1.71 or z > 1.71)

= P( z < -1.71) + P( z > 1.71 )

= 0.0436 + 0.0436

= 0.0872

Answer : P( z < -1.71 or z > 1.71) = 0.0872

Note : From z table we find

P( z < -1.71)= 0.0436

P( z > 1.71 ) =0.0436

Note : graph of z distribution is given below , shaded area is the required probability .