Use the contingency table to the right to calculate the marginal frequencies and find the expected frequency for each cell in the contingency table. Assume that the variables are independent. |
Athlete has |
|||
---|---|---|---|---|
Result |
Stretched |
Not stretched |
||
Injury |
17 |
25 |
||
No injury |
202 |
182 |
(a) Calculate the marginal frequencies and sample size.
Athlete has |
|||
---|---|---|---|
Result |
Stretched |
Not stretched |
Total |
Injury |
17 |
25 |
nothing |
No injury |
202 |
182 |
nothing |
Total |
nothing |
nothing |
nothing |
(b) Find the expected frequency for each cell in the contingency table.
Athlete has |
||
---|---|---|
Result |
Stretched |
Not stretched |
Injury |
nothing |
nothing |
No injury |
nothing |
nothing |
(Round to two decimal places as needed.)
a) Answer :
The marginal frequencies are given in the table below.
Stretched | Not Stretched | Total | |
Injury | 17 | 25 | 17 + 25 = 42 |
No injury | 202 | 182 | 202 + 182 = 384 |
Total | 17 + 202 = 219 | 25 + 182 = 207 |
42 + 384 = 426 |
b) Answer :
The expected frequency is given in the table below.
Stretched | Not Stretched | Total | |
Injury | 21.59 | 20.41 | 42 |
No injury | 197.41 | 186.59 | 384 |
Total | 219 | 207 |
426 |
The expected frequency for a cell is calculated by
value = (row total * column total) / grand total
The value for athlete has stretched and result is injury = (219 * 42) / 426 = 21.59
The value for athlete has not stretched and result is injury = (207 * 42) / 426 = 20.41
The value for athlete has stretched and result is not injury = (219 * 384) / 426 = 197.41
The value for athlete has not stretched and result is not injury = (207 * 384) / 426 = 186.59
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