Question

The weights of bowling balls are normally distributed with mean 11.5 pounds and standard deviation 2.7...

The weights of bowling balls are normally distributed with mean 11.5 pounds and standard deviation 2.7 pounds. A sample of 36 bowling balls is selected. What is the probability that the average weight of the sample is less than 11.03 pounds?

Homework Answers

Answer #1

Solution :

Given that,

mean = = 11.5

standard deviation = = 2.7

n = 36

= 11.5

=  / n = 2.7 / 36=0.45

P( < 11.03) = P[( - ) / < (11.03-11.5) /0.45 ]

= P(z < -1.04)

Using z table  

= 0.1492   

probability= 0.1492

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