Question

We believe that the proportion of vehicles crossing a bridge which are heavy goods vehicles (HGVs) is at most 20%. We count 600 vehicles on a given day, and find that 102 are HGVs. The p-value for the hypothesis test is approximately

Answer 1

ANSWER::

This is the left tailed test .

The null and alternative hypothesis is

H0 : p =0.20

Ha : p <= 0.20

= x / n = 102/600=0.17

P0 = 0.20

1 - P0 = 0.80

Test statistic = z

= - P0 / [P0 * (1 - P0 ) / n]

=0.17-0.20 / [(0.20*0.80) / 600]

= -1.84

=P(z < -1.84) = 0.033 z table

P-value = 0.033

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