Question

Use the given data to find the minimum sample size required to estimate the population proportion. Margin of error: 0.008; confidence level: 98%; ModifyingAbove p with caret and ModifyingAbove q with caret unknown A. 22,184 B. 10,384 C. 20,308 D. 21,207

Answer #1

Solution,

Given that,

= 1 - = 0.5

margin of error = E = 0.008

At 98% confidence level

= 1 - 98%

= 1 - 0.98 =0.02

/2
= 0.01

Z_{/2}
= Z_{0.01} = 2.33

sample size = n = (Z_{ / 2} / E )^{2} *
* (1 -
)

= (2.33 / 0.008)^{2} * 0.5 * 0.5

= 21206.64

sample size = n = 21,207

correct option is = D

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