Solution:- The probability that none of the triplets sit next to each other = 0.97143.
n = 15,
Let first find the probability when all the twins sit together.
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Number of arrangements of three twins in seating of 15= 13!
Twins can also be arranged in themselves = 3!
Total number of arrangements of three twins in seating = 13!*3! = 37,362,124,800
Total number of arrangements of 15 members = 15!
The probability that all the triplets sit next to each other = (37,362,124,800)/15! = 0.02857
The probability that none of the triplets sit next to each other = 1 - 0.02857 = 0.97143
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