Question

The following table provides a frequency distribution for the number of rooms in this​ country's housing units. The frequencies are in thousands.

Rooms	No. of units
1	565565
2	1 comma 4261,426
3	10 comma 94510,945
4	23 comma 38223,382
5	27 comma 93127,931
6	24 comma 68224,682
7	14 comma 64014,640
8plus+	17 comma 28217,282

A housing unit is selected at random. Find the following probabilities.

a. Find the probability that the housing unit obtained has four rooms.

The probability is

nothing.

​(Round to three decimal places as​ needed.)

b. Find the probability that the housing unit obtained has more than four rooms.

The probability is

nothing.

​(Round to three decimal places as​ needed.)

c. Find the probability that the housing unit obtained has one or two rooms.

The probability is

nothing.

​(Round to three decimal places as​ needed.)

d. Find the probability that the housing unit obtained has fewer than one room.

The probability is

nothing.

​(Round to three decimal places as​ needed.)

e. Find the probability that the housing unit obtained has one or more rooms.

The probability is

nothing.

​(Round to three decimal places as​ needed.)

Answer 1

Here is the probability distribution of the number of rooms:

Rooms(x)	No. of units	Probability(P(x))
1	565565	0.0000475218947
2	14,261,426	0.001198323773
3	1,094,510,945	0.09196685416
4	2,338,223,382	0.1964704417
5	2,793,127,931	0.2346940341
6	2,468,224,682	0.2073938688
7	1,464,014,640	0.1230145952
8plus	1,728,217,282	0.1452143603
Total	11901145853	1

a) The probability that the housing unit obtained has four rooms is =P(4) = 0.197

b) The probability that the housing unit obtained has more than four rooms is  

c) The probability that the housing unit obtained has one or two rooms is

d) The probability that the housing unit obtained has fewer than one room is

e) The probability that the housing unit obtained has one or more rooms is = 1 - 0 = 1