The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airports. The maximum possible rating is 10. Suppose a simple random sample of 50 business travelers is selected and each traveler is asked to provide a rating for the Miami International Airport. The ratings obtained from the sample of 50 business travelers follow.
4 | 8 | 9 | 10 | 1 | 1 | 1 | 8 | 8 | 8 | 8 | 7 | 6 |
7 | 8 | 8 | 10 | 9 | 1 | 8 | 7 | 8 | 7 | 9 | 8 | 10 |
6 | 4 | 8 | 1 | 1 | 8 | 8 | 7 | 10 | 9 | 7 | 1 | 7 |
5 | 8 | 4 | 1 | 9 | 8 | 9 | 1 | 1 | 7 | 7 |
Develop a 95% confidence interval estimate of the population mean rating for Miami. Round your answers to two decimal places.
( _____ , _____ )
the necessary calculation table:-
ratings(xi) | |
4 | 16 |
7 | 49 |
6 | 36 |
5 | 25 |
8 | 64 |
8 | 64 |
4 | 16 |
8 | 64 |
9 | 81 |
8 | 64 |
8 | 64 |
4 | 16 |
10 | 100 |
10 | 100 |
1 | 1 |
1 | 1 |
1 | 1 |
9 | 81 |
1 | 1 |
9 | 81 |
1 | 1 |
1 | 1 |
8 | 64 |
8 | 64 |
1 | 1 |
8 | 64 |
8 | 64 |
9 | 81 |
8 | 64 |
7 | 49 |
7 | 49 |
1 | 1 |
8 | 64 |
8 | 64 |
10 | 100 |
1 | 1 |
8 | 64 |
7 | 49 |
9 | 81 |
7 | 49 |
8 | 64 |
9 | 81 |
7 | 49 |
7 | 49 |
7 | 49 |
8 | 64 |
1 | 1 |
6 | 36 |
10 | 100 |
7 | 49 |
sum=316 | sum=2442 |
sample size (n) =50
degrees of freedom = (n-1) = (50-1) = 49
t critical value for 95% confidence level be:-
[ using t distribution table for df = 49,alpha=0.05,both tailed test]
the 95% confidence interval estimate of the population mean rating for Miami be:-
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