Question

A prison official wants to estimate the proportion of cases of recidivism. Examining the records of...

A prison official wants to estimate the proportion of cases of recidivism. Examining the records of 224 convicts, the official determines that there are 97 cases of recidivism. Find the margin of error for a 99% confidence interval estimate for the population proportion of cases of recidivism. (Use 3 decimal places.)

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #2

Solution :

Given that,

Point estimate = sample proportion = = x / n = 97 / 224 = 0.433

1 - = 1 - 0.433 = 0.567

Z/2 = 2.576

Margin of error = E = Z / 2 * (( * (1 - )) / n)

= 2.576 * (((0.433 * 0.567) / 224)

Margin of error = E = 0.085

answered by: anonymous
0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1. A prison official wants to estimate the proportion of cases of recidivism. Examining the records...
1. A prison official wants to estimate the proportion of cases of recidivism. Examining the records of 217 convicts, the official determines that there are 80 cases of recidivism. Find the margin of error for a 95% confidence interval estimate for the population proportion of cases of recidivism.   (Use 3 decimal places.) 2. A prison official wants to estimate the proportion of cases of recidivism. Examining the records of 204 convicts, the official determines that there are 32 cases of recidivism....
Determine the margin of error for a confidence interval to estimate the population proportion for the...
Determine the margin of error for a confidence interval to estimate the population proportion for the following confidence levels with a sample proportion equal to 0.35 and n= 120 the margin of error for a confidence interval to estimate the population portion for 90% confidence level is the margin of error for a confidence interval to estimate the population portion for 95% confidence level is the margin of error for a confidence interval to estimate the population portion for 97%...
1.A confidence interval was constructed to estimate the proportion of smokers in the U.S. Use the...
1.A confidence interval was constructed to estimate the proportion of smokers in the U.S. Use the confidence interval 0.117 < p < 0.412 to find the point estimate, p ^ . Round answer to 3 decimal places. 2.A confidence interval was constructed to estimate the proportion of people who suffer from seasonal allergy. Use the confidence interval 0.466 < p < 0.54 to find the point estimate, p ^ . Round answer to 3 decimal places. 3.A confidence interval was...
Assume that a sample is used to estimate a population proportion p. Find the 99% confidence...
Assume that a sample is used to estimate a population proportion p. Find the 99% confidence interval for a sample of size 224 with 17% successes. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places. < p <
A consumer agency wants to estimate the proportion of all drivers who wear seat belts while...
A consumer agency wants to estimate the proportion of all drivers who wear seat belts while driving. What is the most conservative estimate of the sample size that would limit the margin of error to within 038 of the population proportion for a 99% confidence interval? Round your answer up to the nearest whole number. n=
A manufacturer of cell phones wants to estimate the proportion of the defective phones the factory...
A manufacturer of cell phones wants to estimate the proportion of the defective phones the factory produces. How many cell phones should be sampled and checked in order to estimate the proportion of the defective phones in the population to be within 4% margin of error with 99% confidence? [This is a sample size determination question for proportion. ]
Suppose the survey director wants to estimate the population proportion with a margin of error of...
Suppose the survey director wants to estimate the population proportion with a margin of error of .025 at 99% confidence. How large a sample size is needed to meet the required precision? (A previous sample of similar units yielded .44 for the sample proportion.)
A manufacturer wants to estimate the proportion of defective items in production.18 out of 8,000 randomly...
A manufacturer wants to estimate the proportion of defective items in production.18 out of 8,000 randomly sampled items are found to be defective. a) Establish a 99% confidence interval for the proportion of defective items. b) If we had constructed a confidence interval for the proportion of non-defective items from of the same data, would we have obtained a greater margin of error? c) A proportion of defective items of 3/1000 is considered acceptable. Are we sure of meet the...
The telephone company wants to estimate the proportion of households that would purchase an additional telephone...
The telephone company wants to estimate the proportion of households that would purchase an additional telephone line if it were made available at a substantially reduced installation cost. A random sample of 500 households is selected. The results indicate that 135 of the households would purchase that additional telephone line at a reduced installation cost. Set up a 99% confidence interval estimate of the population proportion of households that would purchase the additional telephone line. Provide responses to the following...
A) Assume that a sample is used to estimate a population proportion p. Find the margin...
A) Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. 90% confidence; n = 341, x = 173 B) Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT