1)
Given
Mean = m = 10
Standard deviation = s = 3
Now
( from Z-table )
= 0.2586
Therefore, the probability that an x value selected at random from this distribution is between 9 and 11 is 0.2586
2.
Given
n = 33
mean = m = 100
standard deviation = s = 15
Now
( from Z-table )
= 0.3707
Therefore, the probability that your sample’s IQ will be 105 or greater is 0.3707
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