Question

A random sample of size 18 taken from a normally distributed population revealed a sample mean...

A random sample of size 18 taken from a normally distributed population revealed a sample mean of 100 and a sample variance of 49. The 95% confidence interval for the population mean would equal: Group of answer choices

93.56 - 103.98

97.65 – 107.35

95.52 -104.65

96.52 – 103.48

Homework Answers

Answer #1

Solution :

t /2,df = 2.110

Margin of error = E = t/2,df * (s /n)

= 2.110 * (7 / 18)

Margin of error = E = 3.48

The 95% confidence interval estimate of the population mean is,

- E < < + E

100 - 3.48 < < 100 + 3.48

96.52 < < 103.48

(96.52 , 103.48)

96.52 – 103.48

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