Question

Mating territory sizes were measured for two species of sparrow. For the Sage sparrow, a measurement of n1 = 20 territories yielded a mean of = 2.60 ha with a standard deviation of s1 = 0.80 ha. For the Brewer’s sparrow, a measurement of n2 = 15 territories yielded a mean of = 1.87 ha with a standard deviation of s2 = 0.75 ha. Test the hypothesis of no difference in mean territory sizes versus the alternative that a difference exits using a 5% level of significance.

I know we use the student's t-distribution table to find the critical t value but the table I have does not have 33 df at 0.05 confidence. How would I calculate the degrees of freedom if I only have 30 and 35?

Answer 1