Question

Due to the popularity of instant messaging and social​ networking, informal elements such as emoticons​ (e.g.,...

Due to the popularity of instant messaging and social​ networking, informal elements such as emoticons​ (e.g., the symbol​ ":)" to represent a​ smile) and abbreviations​ (e.g., "LOL" for​ "laughing out​ loud") have worked their way into​ teenagers' school writing assignments. A survey interviewed 800 randomly selected teenagers by telephone on their writing habits.​ Overall, 431 of the teenagers admitted using at least one informal element in school writing assignments. Based on the survey​ results, construct a 90​% confidence interval for the proportion of all teenagers who have used at least one informal element in school writing assignments. Give a practical interpretation of the interval.

The 90​% confidence interval is ​( ​, ).

Interpret the interval. Choose the correct answer below.

A. One can be 10% confident that the interval contains the sample population proportion of all teenagers who have used at least one informal element in school writing assignments.

B. One can be 10% confident that the interval contains the true population proportion of all teenagers who have used at least one informal element in school writing assignments.

C. One can be 90​% confident that the interval contains the sample population proportion of all teenagers who have used at least one informal element in school writing assignments. Your answer is not correct.

D. One can be 90​% confident that the interval contains the true population proportion of all teenagers who have used at least one informal element in school writing assignments.

Homework Answers

Answer #1

The statistical software output for this problem is:

From above output:

90% confidence interval:

(0.509, 0.568)

Interpretation:

One can be 90​% confident that the interval contains the true population proportion of all teenagers who have used at least one informal element in school writing assignments.

Option D is correct.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Due to the popularity of instant messaging and social​networking, informal elements such as emoticons​ (e.g., the...
Due to the popularity of instant messaging and social​networking, informal elements such as emoticons​ (e.g., the symbol​":)" to represent a​ smile) and abbreviations​ (e.g., "LOL" for​"laughing out​ loud") have worked their way into​ teenagers' school writing assignments. A survey interviewed 900 randomly selected teenagers by telephone on their writing habits.​ Overall, 446 of the teenagers admitted using at least one informal element in school writing assignments. Based on the survey​ results, construct a 90​% confidence interval for the proportion of...
6.18 Is college worth it? Part II: Exercise 6.16 presents the results of a poll where...
6.18 Is college worth it? Part II: Exercise 6.16 presents the results of a poll where 48% of 331 Americans who decide to not go to college do so because they cannot afford it. (a) Calculate a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it, and interpret the interval in context. lower bound: _________ (please round to four decimal places) upper bound: _________(please round to four decimal places)...
5.22 High School and beyond, Part II: We considered the differences between the reading and writing...
5.22 High School and beyond, Part II: We considered the differences between the reading and writing scores of a random sample of 200 students who took the High School and Beyond Survey in Exercise 5.21. The mean and standard deviation of the differences are x̄read-write = -0.545 and 8.887 points respectively. (a) Calculate a 95% confidence interval for the average difference between the reading and writing scores of all students. lower bound: points (please round to two decimal places) upper...
5.22 High School and beyond, Part II: We considered the differences between the reading and writing...
5.22 High School and beyond, Part II: We considered the differences between the reading and writing scores of a random sample of 200 students who took the High School and Beyond Survey in Exercise 5.21. The mean and standard deviation of the differences are x̄read-write = -0.545 and 8.887 points respectively. (a) Calculate a 95% confidence interval for the average difference between the reading and writing scores of all students. lower bound: points (please round to two decimal places) upper...
a. A random sample of elementary school children in New York state is to be selected...
a. A random sample of elementary school children in New York state is to be selected to estimate the proportion p who have received a medical examination during the past year. The survey found that x = 468 children were examined during the past year. Construct the 95 % confidence interval estimate of the population proportion p if the sample size was n=600 . Give your confidence interval bounds to at least 4 decimal places. b) Which of the following...
1. a survey of 2000 randomly selected musician found that 304 of them are left-handed. The...
1. a survey of 2000 randomly selected musician found that 304 of them are left-handed. The 92% confidence interval for the true proportion of all musicians that are left-handed is (0.139, 0.165). What is the best conclusion to draw from this interval? There is a 90% chance that between 13.9% and 16.5% of any sample of musicians will be left-handed We can be 90% confident that the constructed confidence interval captures the unknown population proportion of musicians that are left-handed...
Are you likely to purchase an item promoted by a celebrity on a social media​ site?...
Are you likely to purchase an item promoted by a celebrity on a social media​ site? According to a​ survey, 27​% of social media users have made such a purchase. Complete parts​ (a) through​ (d) below. a. Suppose that the survey had a sample size of nequals=900. Construct a 90 %90% confidence interval estimate for the population proportion of social media users that have purchased an item promoted by a celebrity on a social media site. ____less than or equals≤piπless...
Close Friends: The 2004 General Social Survey (GSS) interviewed a random sample of adult Americans. For...
Close Friends: The 2004 General Social Survey (GSS) interviewed a random sample of adult Americans. For one question the interviewer asked: “From time to time, most people discuss important matters with other people. Looking back over the last six months – who are the people with whom you discussed matters important to you? Just tell me their first names or initials.” The interviewer then recorded how many names or initials the respondent mentioned. Results are tallied in the following table:...
I only need answers for number 4 & 5. (Just 2 numbers) 1.) The mean instant...
I only need answers for number 4 & 5. (Just 2 numbers) 1.) The mean instant messaging bill is P32.79 per household. A sample of 50 households showed a sample mean of P30.63. Use a population standard deviation of σ=5.60. Formulate hypothesis for a test to determine whether the sample data support the conclusion that the mean monthly instant messaging bill is less than the national mean of P32.79. What is the value of the test statistic? What is the...
1. When constructing a confidence interval to estimate a population proportion, what affects the size of...
1. When constructing a confidence interval to estimate a population proportion, what affects the size of the margin of error? A. The sample size B. The sample proportion C. The confidence level D. All of the above affect the size of the margin of error E. None of the above affect the size of the margin of error 2. What percentage of couples meet through online dating apps? A survey of a random sample of couples finds that 12% say...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT